1. The diameter of longitudinal bars in a column should not be less than ?

4 mm

8 mm

12 mm

16 mm

Answer: 12 mm

Explanation:


2. The diameter of bars used for distribution reinforcement in slabs, may vary from ?

2 to 4 mm

4 to 6 mm

6 to 8 mm

8 to 12 mm

Answer: 6 to 8 mm

Explanation:


3. The maximum shear stress in a rectangular beam is ............. times of average shear stress ?

1.15

1.25

1.50

1.75

Answer: 1.50

Explanation:


4. The neutral axis in a T-beam section falls ?

within the flange

outside the flange

either (a) or (b)

none of these

Answer: either (a) or (b)

Explanation:


5. The pre-stressed concrete induces artificially ........... stresses in a structure before it is loaded ?

tensile

compressive

shear

tear

Answer: compressive

Explanation:


6. In stairs spanning horizontally, the distribution reinforcement provided in the form of ......... meter rods at 30 cm centre to centre is normally adequate ?

4 mm

6 mm

10 mm

12 mm

Answer: 6 mm

Explanation:


7. The bond between steel and concrete is mainly due to ?

pure adhesive resistance

frictional resistance

mechanical resistance

all of these

Answer: all of these

Explanation:


8. If the area of tensile steel reinforcement is doubled, the moment of resistance of the beam increases only by about ?

12%

22%

32%

42%

Answer: 22%

Explanation:


9. In a beam section, if the steel reinforcement is of such a magnitude that the permissible stresses concrete and steel are developed simultaneously, the section is known as ?

balanced section

critical section

economical section

any one of these

Answer: any one of these

Explanation:


10. Which of the following statement is correct ?

For bridge slabs, the amount of reinforcement is taken as 0.6 % of gross concrete area

In a circular slab, the reinforcement is provided at the concave side of the slab

The transverse reinforcement in a simply supported slab distributes the temperature stress

all of the above

Answer: The transverse reinforcement in a simply supported slab distributes the temperature stress

Explanation: